[squid-users] Calculation of throughput...

Hi guys (m/f),

Could you help me on the following puzzle?

When I look at the Squid-logfiles, column 5 is the number of bytes from a
download, number 2 is the number of milliseconds that transaction took,
right?

So when I divide the two, like bytes/(time/1000), I get bytes/second, right?

If I do that for all succeeded transactions ( squid-status <>
"/[4-6][0-9]\{2\}", knowing how good you are in regular expressions), I get
the following results:

Commands used:
Number of succeeded transactions: grep -v "/[4-6][0-9]\{2\}" access.log | wc
-l
Avg transaction time: grep -v "/[4]6[0-9]\{2\}" access.log | awk '{time +=
$2} END {print time/NR}'
Avg download size: grep -v "/[4]6[0-9]\{2\}" access.log | awk '{size += $5}
END {print size/NR}'
Avg download speed: grep -v "/[4]6[0-9]\{2\}" access.log | awk '{time += $2;
size += $5} END {print (size/(time/1000))/1024}'

which give me the following results:

European Proxy (with a 6Mbit-internetlink):
# transactions: 1,554,209
avg time: 1,622.91 ms
avg size: 5,122.98 bytes
avg speed: 3.08 kb/sec

American Proxy (with a 4Mbit-internetlink):
# transactions: 477,666
avg time: 2,124.19 ms
avg size: 6,508.64 bytes
avg speed: 2.99 kb/sec

Could this all be right? That means that our internetlinks are slower that a
normal dialup-line....
Or am I making some mistake here?

Thanks in advance.

Peter

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Received on Thu Aug 15 2002 - 03:42:03 MDT